"use strict"; // Copyright (c) Microsoft Corporation. All rights reserved. Licensed under the MIT license. // See LICENSE in the project root for license information. Object.defineProperty(exports, "__esModule", { value: true }); exports.ApiNameMixin = void 0; const _name = Symbol('ApiNameMixin._name'); /** * Mixin function for {@link (ApiNameMixin:interface)}. * * @param baseClass - The base class to be extended * @returns A child class that extends baseClass, adding the {@link (ApiNameMixin:interface)} functionality. * * @public */ function ApiNameMixin(baseClass // eslint-disable-next-line @typescript-eslint/no-explicit-any ) { class MixedClass extends baseClass { // eslint-disable-next-line @typescript-eslint/no-explicit-any constructor(...args) { super(...args); const options = args[0]; this[_name] = options.name; } /** @override */ static onDeserializeInto(options, context, jsonObject) { baseClass.onDeserializeInto(options, context, jsonObject); options.name = jsonObject.name; } get name() { return this[_name]; } /** @override */ get displayName() { return this[_name]; } /** @override */ serializeInto(jsonObject) { super.serializeInto(jsonObject); jsonObject.name = this.name; } } return MixedClass; } exports.ApiNameMixin = ApiNameMixin; /** * Static members for {@link (ApiNameMixin:interface)}. * @public */ (function (ApiNameMixin) { /** * A type guard that tests whether the specified `ApiItem` subclass extends the `ApiNameMixin` mixin. * * @remarks * * The JavaScript `instanceof` operator cannot be used to test for mixin inheritance, because each invocation of * the mixin function produces a different subclass. (This could be mitigated by `Symbol.hasInstance`, however * the TypeScript type system cannot invoke a runtime test.) */ function isBaseClassOf(apiItem) { return apiItem.hasOwnProperty(_name); } ApiNameMixin.isBaseClassOf = isBaseClassOf; })(ApiNameMixin = exports.ApiNameMixin || (exports.ApiNameMixin = {})); //# sourceMappingURL=ApiNameMixin.js.map